Spoiler to Python Challenge (help!!!)

[Christos Georgiou]

On Tue, 27 Sep 2005 10:42:20 -0500, rumours say that Terry Hancock
<hancock at anansispaceworks.com> might have written:

>This works:
>
>>>> bz2.decompress(eval(repr(user)))
>'huge'

>This may have some security issues, though, since it evaluates essentially
>any expression given for user.  I'd be interested to know if someone
>knows a more secure way.

given

a = "a tab\\x09between"

this is more secure than eval:

b= a.decode("string_escape")
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