after sorted from the lists

Micah Elliott mde at micah.elliott.name
Tue Nov 22 11:07:39 EST 2005


On Nov 22, Ben Bush wrote:
> I have a list:
> [[1,2],[2,1],[3,1],[1,4],[3,3],[1,4]]
> How to remove all the duplicate or same after sorted from the lists?
> That is, [1,2] and [2,1] are the same after sorting them.
> I want the result to be:
> [[1,2],[3,1],[1,4],[3,3]]

You've described the code in words.  Next time show the code you
tried.  Here's one possible solution.

First sort each sublist.

    >>> L1 = [[1,2],[2,1],[3,1],[1,4],[3,3],[1,4]]
    >>> for i in L1:
    ...     i.sort()
    ...
    >>> L1
    [[1, 2], [1, 2], [1, 3], [1, 4], [3, 3], [1, 4]]

Then add L1's unique items to a new list L2.

    >>> L2 = []
    >>> for i in L1:
    ...     if i not in L2:
    ...         L2.append(i)
    ...
    >>> L2
    [[1, 2], [1, 3], [1, 4], [3, 3]]

This is not identical to your said output, but it sounds like 
[1,3] == [3,1] for your purposes.

-- 
_ _     ___
|V|icah |- lliott             <><             mde at micah.elliott.name
" "     """



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