Encryption with Python?

Christos TZOTZIOY Georgiou tzot at sil-tec.gr
Fri May 13 05:06:54 EDT 2005


On Sat, 7 May 2005 13:51:40 +0200, rumours say that "Anthra Norell"
<anthra.norell at tiscalinet.ch> might have written:

>Here's the challenge. Prove this breakable
>
>'\x10\x88d\x1d\xba\xa1\xdcK\x05w\x02/s\xa7Q0\xeb8\xb6Gx\xef\xcb\x1e=\xf5\x7f
>\x9bI\xcb(\x87>\xa5\x04\xc1soF\xfd\xc6\xc6\xd9|\x971\xdb\xcdT\tw#\x86a\xdc\x
>b8P\xfb=n\xda\x80\x9f\x84m\x12\x98\x98\xca=o\x0b\x8e\x08O\xb7\x0b\x04SC\x96\
>xc7\xab*\x0b\x996\x06\x86\x83(\x8dQ\x9eG\x8f$\xb2x)\xa9fv\x0c1B\x9b\r\xde\xf
>fc\x08'

and given that

>I rolled my own for relatively short sequences, like passwords. The key is
>an integer. To decrypt use the negative encryption key. I consider the
>encryption unbreakable, as it is indistinguishable from a random sequence.

can we suppose that the encrypted text above are the details of your
credit card (number, name as written on it, expiry date, billing address
and your first dog's name)?  Do you trust the 'unbreakability' of your
algorithm that much?
-- 
TZOTZIOY, I speak England very best.
"Be strict when sending and tolerant when receiving." (from RFC1958)
I really should keep that in mind when talking with people, actually...



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