How to create linked list automatically
Shahriar Shamil Uulu
shamilsons at gmail.com
Tue Dec 20 02:49:42 EST 2005
Thank you very much to all,
we have figured it out, how to make it work,
w=[]
for i in range(10):
node=Node(i)
w.append(node)
for i in range(10):
a=w[i]
if i+1>9:
b=w[9]
a.next=b
else:
b=w[i+1]
a.next=b
we have runned in this way
Dave Hansen wrote:
> On Mon, 19 Dec 2005 20:51:39 +0000 in comp.lang.python, Simon Brunning
> <simon at brunningonline.net> wrote:
>
> >I haven't the time (or inclination) to sort out all your problems
> >here, but one thing jumps out at me:
> >
> >On 12/19/05, Shahriar Shamil Uulu <shamilsons at yahoo.com> wrote:
> >> class Node:
> >> def __init__(self,name=None,next=None):
> >> self.name=name
> >> self.next=next
> >>
> >> def __str__(self):
> >> return str(self.name)
> >
> >Your Node classes str() prints the instances self.name attribute,
> >which is set by an optional named argument on the initialiser...
> >
> >> w=[]
> >> for i in range(10):
> >> node=Node(i)
> >
> >... but you aren't providing this argument when you build your Node objects...
>
> Actually, he is. Look closer.
>
> As /F pointed out, his problem is in the linking. By making a small
> modification to his code, I was able to get it to print
>
> 1 2 3 4 5 6 7 8 9 None
>
> As (I assume) was expected. I'd post the code, but the margin is too
> small to contain it... Besides, I'd like the OP to figure it out
> himself.
>
> Regards,
> -=Dave
>
> --
> Change is inevitable, progress is not.
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