ignoring keywords on func. call

[Steve Holden]

Brano Zarnovican wrote:
>>>Q: Can you call 'f' with keywords that will be
>>> ignored, without changing 'f's definition ?
>>
>>no.
> 
> 
> OK. Thank you for an answer.
> 
> 
>>what's the use case?
> 
> 
> I have extended the dict class, so that my __getitem__ accepts an
> optional parameter
> 
[...]
> 
> But it still doesn't guarantee that __getitem__ accepts keywords.
> (What if somebody will extend the Tree class and overlook the
> definition of __getitem__ and define a "classic" one)
> 
Then they haven't programmed to your API, and deserve to be rewarded 
with an error message - it's the only way they can be informed they 
aren't writing to your standard, surely?

regards
  Steve
-- 
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