how can I extract all urls in a string by using re.findall() ?

[Sidharth Kuruvila]

Reading the documentation on re might be helpfull here :-P

findall returns a tuple of all the groups in each match.

You might find finditer usefull.

for m in re.finditer(url, html) :
    print m.group()

or you could replace all your paranthesis with the non-grouping
version. That is, all brackets (...) with (?:...)


On Apr 7, 2005 7:35 AM, could ildg <could.net at gmail.com> wrote:
> I want to retrieve all urls in a string. When I use re.fiandall, I get
> a list of tuples.
> My code is like below:
> 
> [code]
> url=unicode(r"((http|ftp)://)?(((([\d]+\.)+){3}[\d]+(/[\w./]+)?)|([a-z]\w*((\.\w+)+){2,})([/][\w.~]*)*)")
> m=re.findall(url,html)
> for i in m:
>    print i
> [/code]
> 
> html is a variable of string type which contains many urls in it.
> the code will print many tuples, and each tuple seems not to represent
> a url. e.g, one of them is as below:
> 
> (u'http://', u'http', u'image.zhongsou.com/image/netchina.gif', u'',
> u'', u'', u'', u'image.zhongsou.com', u'.com', u'.com',
> u'/netchina.gif')
> 
> Why is there two "http" in it? and why are there so many ampty strings
> in the tupe above? It's obviously not a url. How can I get the urls
> correctly?
> 
> Thanks in advance.
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