cannot pass a variable from a function

[Kirk Strauser]

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At 2004-06-16T22:46:42Z, "Doug Jordan" <djordan8 at houston.rr.com> writes:

> #function suppose to return variable
> def fctn2(c):
>     for h in c:
>         q=h*80
>         return q
>
> def prntfctn(y):
>     for j in y:
>         print j
>
> fctn2(list)
> prntfctn(q)

The name "q" only exists inside the scope of the fctn2 variable.  If you
want it present inside the global scope, assign it there:

    q = fctn2(list)
    prtnfctn(q)

That should do what you want.  Note that I'm unaware of any modern
programming language that would allow a function to assign a value to a
global variable without explicitly requesting it.  If such a thing exists,
then I highly recommend you avoid it at all costs.
- -- 
Kirk Strauser
The Strauser Group
Open. Solutions. Simple.
http://www.strausergroup.com/
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