cannot pass a variable from a function

[Doug Jordan]

Kirk,
Thanks for your input, hoever that is not exactly what I am trying to do.
I understand that q is local scope.  I was trying to return q and make a
call to the function using another variable with global scope.

In other language
subroutine foo(b,c)
    c=b*1000
return
call foo(q,r)
where q and r are defines and same type as b,c as  function
How do I do this in python.  I need to perform operations on a variable and
pass the new variable to the program.
Hope this might clear it up.

Doug
"Kirk Strauser" <kirk at strauser.com> wrote in message
news:87smcvuma1.fsf at strauser.com...
-----BEGIN PGP SIGNED MESSAGE-----
Hash: SHA1

At 2004-06-16T22:46:42Z, "Doug Jordan" <djordan8 at houston.rr.com> writes:

> #function suppose to return variable
> def fctn2(c):
>     for h in c:
>         q=h*80
>         return q
>
> def prntfctn(y):
>     for j in y:
>         print j
>
> fctn2(list)
> prntfctn(q)

The name "q" only exists inside the scope of the fctn2 variable.  If you
want it present inside the global scope, assign it there:

    q = fctn2(list)
    prtnfctn(q)

That should do what you want.  Note that I'm unaware of any modern
programming language that would allow a function to assign a value to a
global variable without explicitly requesting it.  If such a thing exists,
then I highly recommend you avoid it at all costs.
- -- 
Kirk Strauser
The Strauser Group
Open. Solutions. Simple.
http://www.strausergroup.com/
-----BEGIN PGP SIGNATURE-----
Version: GnuPG v1.2.4 (GNU/Linux)

iD8DBQFA0NS95sRg+Y0CpvERAlGRAKCkUJTaBJIckaWCvM2qkEmA8BDSEgCaAgcp
u44PX2uPlSMGYAV4VG5jaC8=
=G3qn
-----END PGP SIGNATURE-----