regex help for a newbie

[marco]

Marco Herrn <herrn at gmx.net> writes:

> On 2004-04-06, marco <marco at reimeika.ca> wrote:
> > Marco Herrn <herrn at gmx.net> writes:
> >> the parts in a recursive function. So the thing I want to achieve here
> >> is to extract %(BBB%(CCC)BBB) and %(DDD).
> >
> > p1, p2 = "aaa%(BBB%(CCC)BBB)aaa%(DDD)aaa".split("aaa")[1:-1]
> 
> Doesn't help, since I do not know that there is the string "aaa". It was
> just an example. I do not know any of the strings/characters. The only
> thing I know is that a percent sign indicates that the content inside
> the following parentheses is an expression that has to be evaluated.

Ah, that's clearer ;)

Does the "aaa"-type string really show up three times? Or is it actually:

"maybeeggs%(BBB%(CCC)BBB)maybeham%(DDD)maybespam"

If it's like you describe then maybe:

"aaa%(BBB%(CCC)BBB)aaa%(DDD)aaa".split("aaa%(BBB%(CCC)BBB)aaa%(DDD)aaa".split("%(")[0])[1:-1]

helps (but I doubt it -- I guess you'll need a real parser :)

Cheers,

--
marco at reimeika.ca
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