python 2.3's lambda behaves old fashioned

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Uwe Schmitt <uwe.schmitt at procoders.net> wrote in message news:<c6r3qo$1574k$1 at hades.rz.uni-saarland.de>...
> Hi,
> 
> I just tried (Python 2.3)
> 
>     li = [ lambda x: x*a for a in range(10) ]
> 
> which results in 
> 
>     li[0](1) = 9
>     ...
>     li[9](1) = 9
> 
> In order to achieve the intended result I had to fall back on the
> following trick:
> 
>     li = [ lambda x,a=a: x*a for a in range(10)]
> 
> which leads to the expected result.
> 
> Any explanations ???
> 
> Greetings, Uwe.

This should be in  the FAQ. Here is a recent thread on the subject:

http://groups.google.it/groups?hl=it&lr=&ie=UTF-8&oe=UTF-8&threadm=95aa1afa.0402272327.29828430%40posting.google.com&rnum=1&prev=/groups%3Fhl%3Dit%26lr%3D%26ie%3DUTF-8%26oe%3DUTF-8%26q%3Dsimionato%2Bscope%2Brules%26meta%3Dgroup%253Dcomp.lang.python.*

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