python 2.3's lambda behaves old fashioned

[Uwe Schmitt]

Hi,

I just tried (Python 2.3)

    li = [ lambda x: x*a for a in range(10) ]

which results in 

    li[0](1) = 9
    ...
    li[9](1) = 9

In order to achieve the intended result I had to fall back on the
following trick:

    li = [ lambda x,a=a: x*a for a in range(10)]

which leads to the expected result.

Any explanations ???

Greetings, Uwe.
 

-- 
Dr. rer. nat. Uwe Schmitt   http://www.procoders.net                      
schmitt at procoders.net      "A service to open source is a service to mankind."