invert dictionary with list &c

[Des Small]

anton muhin <antonmuhin.REMOVE.ME.FOR.REAL.MAIL at rambler.ru> writes:

> Des Small wrote:
> > Des Small <des.small at bristol.ac.uk> writes:
> >
> >>anton muhin <antonmuhin.REMOVE.ME.FOR.REAL.MAIL at rambler.ru> writes:
> > [...]
> 
> Or like this:
> 
> def dict_update(iter, func, default, d):
>      def process_element(d, e):
>          d[e[0]] = func(d.get(e[0], default), *e[1:])
>          return d
> 
>      return reduce(process_element, iter, d)
> 
> def count(l):
>      return dict_update(l, lambda x: x + 1, 0, {})

With these I get:

>>> count(["yes", "yes", "no"])

Traceback (most recent call last):
  File "<stdin>", line 1, in ?
  File "<stdin>", line 2, in count
  File "<stdin>", line 5, in dict_update
  File "<stdin>", line 3, in process_element
TypeError: <lambda>() takes exactly 1 argument (3 given)

I tried to write something that would work on more generic arguments,
but I couldn't do it without explicit type checking, so I gave up.

[...]

Des
has now embalmed versions in his utils collection.

-- 
"[T]he structural trend in linguistics which took root with the
International Congresses of the twenties and early thirties [...] had
close and effective connections with phenomenology in its Husserlian
and Hegelian versions." -- Roman Jakobson