Most efficient unzip - inverse of zip?
Pearu Peterson
pearu at cens.ioc.ee
Tue Mar 26 15:50:14 EST 2002
Hi,
What would be the most efficient way to unzip zipped sequences
in Python 2.2?
For example, consider
a_b = zip(a,b) # where a and b are some sequences
a_b.sort()
a,b = unzip(a_b)
For a start, I have
def unzip(seq):
ns = range(len(seq[0]))
r = [[] for i in ns]
[r[i].append(s[i]) for i in ns for s in seq]
return tuple(r)
Is there any better algorithm for unzip?
Regards,
Pearu
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