Most efficient unzip - inverse of zip?

[Emile van Sebille]

Pearu Peterson
> What would be the most efficient way to unzip zipped sequences 
> in Python 2.2?
> 
> For example, consider
> 
>  a_b = zip(a,b)  # where a and b are some sequences
>  a_b.sort()
>  a,b = unzip(a_b)
>

You'd need to define efficient better, but I'd try something like:

>>> z = zip(range(52),string.letters)
>>> a = [ii for ii,jj in z]
>>> b = [jj for ii,jj in z]

-- 

Emile van Sebille
emile at fenx.com

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