"Jim" <jkring at calbay.com> wrote in message
news:89a9b6ce.0110030954.7ee3043f at posting.google.com...
> The following code is used to create a class. If I make an instance
> of the class called "k", then calling k.func1(23) will print
> "k.func1(23)", and calling k.func2() will print "k.func2()" and return
> 12. The problem occurs when I nest the functions like this:
> k.func1(k.func2()). This prints "k.func2()", "k.func2(12)" when I
> really want it to print "k.func2()", "k.func1(12)". It gets more
> interesting when I do something like k.func1(k.func2() + k.func3()).
> This results in a printout of "k.func2()", "k.func3()", "k.func2(12)".
>
> What's up with this, and it a bug or a feature of python? It seams
> like the __getattr__ is not being called/refreshed in the external
> function if it is also called inside the function.
>
> Thanks for any help
>
> -Jim
>
> ****** Code *******
>
> class klass:
>
> def __init__(self, name):
> self.name = name
>
> def __getattr__(self, a):
>
> self.string = a
> return(self.nop)
>
> def __repr__(self):
> return ''
>
> def nop(self, a = None):
>
> if (a == None):
> #pass
> print self.name + '.' + self.string + '()'
> return 12
>
> else:
> #pass
> print self.name + '.' + self.string + '(' + str(a) + ')'
Well, what do you expect when you are trying to save state for a number of
recursive calls in the same instance variable. Try adding
print "I just set 'self.string' to", a
inside the __getattr__() method. You will see that the setting of func1 is
overwritten by the setting of func2, because of the call structure.
regards
Steve
--
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