__getatr__ question

[Janko Hauser]

It's the order of evaluation, and that you change the instance
inplace.

If you change __getattr__ to
    def __getattr__(self, a): 
 
        self.string = a
        print 'self.string = %s' % self.string
        return(self.nop) 

This becomes obvious. The output of  k.func1(k.func2(12)) looks then

self.string = func1
self.string = func2
k.func2(12)
k.func2()

Although I must admit, that I also expected that the argument of a
function call is also evaluated before the function is called.

So it does not seem to look like a bug, but perhaps there are more
insights available :-).

__Janko

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