Check URL --> Simply?
JS
joesalt at ireland.com
Wed Aug 15 10:33:59 EDT 2001
One question regarding handling directories from the example below...
>>> checkURL('http://www.slashdot.org')
1
>>> checkURL('http://www.slashdot.org/notadirectory')
1
In the second example, the directory doesn't exist, yet I am returned
1? Is there a way to handle this?
As always, Thanks!
Alex <new_name at mit.edu> wrote in message news:<etd3d6uf05b.fsf at lola-granola.mit.edu>...
> import urllib
>
> def checkURL(url):
> try: urllib.urlopen(url)
> except IOError: return 0
> return 1
>
> if __name__ == '__main__':
> assert checkURL('http://slashdot.org')
> assert not checkURL('http://foo')
>
> HTH.
> Alex.
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