statically nested scopes

[Paul Prescod]

On Sat, 4 Nov 2000, Robin Becker wrote:

> How can this work when different paths define different 
> variables.

You're probing a dark corner of Python, but I don't think that 
statically nested scopes makes it any worse than it is.

> ie
> 
> G=0
> def A():
>   for i in range(3):
>     if i>=2:

>       G=i*i
>     def B():
>       return G+2
>     print B()

I claim the answer would be the same as if you remove the
nested function altogether:

G=0
def A():
    for i in range(3):
        if i>=2:
            G=i*i
        print G
A()

It is all figured out statically, not dynamically so G is either 
always a local or always a global -- in this case always a local
because it is assigned to.

 Paul Prescod