HELP Newbie solve this Problem

[Felix Thibault]

Are 10, 20, and 30 continuations ?

At 21:10 3/23/00 -0800, Dennis Lee Bieber wrote:
>On Fri, 24 Mar 2000 03:43:38 GMT, race9047 at my-deja.com declaimed the
>following in comp.lang.python:
>	I must be from a different world then... The second part is what
>I'd find easy... even in FORTRAN (maybe too easy in FORTRAN)
>
>	integer	counts(26)	/ 26 * 0 /	! or is it 0 * 26?
>	character	line*132	! set for the longest line the
>					! the data file can contain
>	open(10, file="data", status="old")
>	read(10, '(a132)', iostat=ios) line
>   10	continue
>	if (ios .eq. 0) then
> 	    do 20 i=1, 132		! or the line length max
>		if (line(i:i) .ge. 'a' .and. line(i:i) .le. 'z') then
>			inx = ichar(line(i:i)) - ichar('a') + 1
>			counts(inx) = counts(inx) + 1
>		elseif (line(i:i) .ge. 'A' .and. line(i:i) .le. 'Z')
>     x							then
>			inx = ichar(line(i:i)) - ichar('A') + 1
>			counts(inx) = counts(inx) + 1
>		else
>			continue	! just my style
>		endif
>   20	    continue
>	    read(10, '(a132)', iostat=ios) line
>	goto 10
>	endif
>	close(10)
>	do 30 i=1, 26
>	    print *, char(i), '     ', counts(i)
>   30	continue
>	stop
>
>
>	It would look much cleaner in Python, and I'd use case
>conversion modules rather than the duplicates in the IF statements...
>
>	
>--
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