ftplib sendcmd

[Gordon McMillan]

Bill Scherer wrote


> I'm having trouble with ftplib's sendcmd method (Python 1.5.2 on
> RH linux 6.1):
> 
> >>> ftp = ftplib.FTP(host, user, password)
> >>> ftp.sendcmd('umask 002')
> Traceback (innermost last):
>   File "<stdin>", line 1, in ?
>   File "/usr/local/lib/python1.5/ftplib.py", line 228, in sendcmd
>     return self.getresp()
>   File "/usr/local/lib/python1.5/ftplib.py", line 201, in getresp
>     raise error_perm, resp
> ftplib.error_perm: 500 'UMASK 002': command not understood.
> >>>
> 
> The umask command does, of course, work using a standard ftp
> client to the same host.
> 
> Other commands, chmod, etc, suffer equal fate.
> 
> Is this not what sendcmd is for? What am I doing wrong?  Thanks!

These are not rcf 959 commands. GNU ftpd will support them 
as SITE UMASK x and SITE CHMOD mod file.


- Gordon