ftplib sendcmd

[Bill Scherer]

Thanks Gordon! This is the answer I needed.  It all works great now.

Thanks again,

Bill

Gordon McMillan wrote:

> Bill Scherer wrote
>
> > I'm having trouble with ftplib's sendcmd method (Python 1.5.2 on
> > RH linux 6.1):
> >
> > >>> ftp = ftplib.FTP(host, user, password)
> > >>> ftp.sendcmd('umask 002')
> > Traceback (innermost last):
> >   File "<stdin>", line 1, in ?
> >   File "/usr/local/lib/python1.5/ftplib.py", line 228, in sendcmd
> >     return self.getresp()
> >   File "/usr/local/lib/python1.5/ftplib.py", line 201, in getresp
> >     raise error_perm, resp
> > ftplib.error_perm: 500 'UMASK 002': command not understood.
> > >>>
> >
> > The umask command does, of course, work using a standard ftp
> > client to the same host.
> >
> > Other commands, chmod, etc, suffer equal fate.
> >
> > Is this not what sendcmd is for? What am I doing wrong?  Thanks!
>
> These are not rcf 959 commands. GNU ftpd will support them
> as SITE UMASK x and SITE CHMOD mod file.
>
> - Gordon