Should numpy.sqrt(-1) return 1j rather than nan?

[David Goldsmith]

I find that acceptable for my purposes, but is there some way we can 
minimize the "surprise(s)"  for newbies?  (I know some suggestions have 
been put forward in this thread, but I don't know enough to cast a vote 
one way or another for any of those, just a vote for "please do it".)  
And, in closing, I too would like to: thank you very much for all your 
work - despite my "emotional outburst," I am generally very happy using 
numpy and regard it as an excellent product.

DG

Travis Oliphant wrote:
> David Goldsmith wrote:
>
>   
>> Got it.  And if I understand correctly, the import order you specify in 
>> the little mynumpy example you included in your latest response to 
>> Fernando will result in any "overlap" between numpy and 
>> numpy.lib.scimath to call the latter's version of things rather than the 
>> former's, yes?
>>  
>>
>>     
>
> Right.  The last import will be used for any common-names (variables get 
> re-bound to the new functions...)
>
> -Travis
>
>
> -------------------------------------------------------------------------
> Using Tomcat but need to do more? Need to support web services, security?
> Get stuff done quickly with pre-integrated technology to make your job easier
> Download IBM WebSphere Application Server v.1.0.1 based on Apache Geronimo
> http://sel.as-us.falkag.net/sel?cmd=lnk&kid=120709&bid=263057&dat=121642
> _______________________________________________
> Numpy-discussion mailing list
> Numpy-discussion at lists.sourceforge.net
> https://lists.sourceforge.net/lists/listinfo/numpy-discussion
>   


-------------------------------------------------------------------------
Using Tomcat but need to do more? Need to support web services, security?
Get stuff done quickly with pre-integrated technology to make your job easier
Download IBM WebSphere Application Server v.1.0.1 based on Apache Geronimo
http://sel.as-us.falkag.net/sel?cmd=lnk&kid=120709&bid=263057&dat=121642