Should numpy.sqrt(-1) return 1j rather than nan?

[Travis Oliphant]

David Goldsmith wrote:

>Got it.  And if I understand correctly, the import order you specify in 
>the little mynumpy example you included in your latest response to 
>Fernando will result in any "overlap" between numpy and 
>numpy.lib.scimath to call the latter's version of things rather than the 
>former's, yes?
>  
>

Right.  The last import will be used for any common-names (variables get 
re-bound to the new functions...)

-Travis


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