[Tutor] Using break, else with for loop

[Alan Gauld]

On 11/10/2020 07:38, Manprit Singh wrote:
> Dear sir ,
> 
> Consider a problem where I have to check if a list contains an odd number.

> l = [2, 4, 6, 5, 8, 3]
> for i in l:
>     if i % 2 != 0:
>         print("Odd number found in list")
>         break
> else:
>     print("List does not contain odd number")

That's a valid solution.
A slightly shorter version is:

if any(n%2 for n in l):
   print("Odd no found in list")



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Alan G
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