[Tutor] modification to a list

[Mark Lawrence]

On 22/04/2020 15:44, shubham sinha wrote:
> Hi,
> Q. The skip_elements function returns a list containing every other element
> from an input list, starting with the first element. Complete this function
> to do that, using the for loop to iterate through the input list.
> my code:
> def skip_elements(elements):
>      new_list = [ ]
>      i = 0
>      for element in elements:
>          if "element" != "elements(i):
>              new_list.append(element)
> 
>          i += 2
>      return new_list

You don't need any of the above code, you can do the entire operation in 
one hit with the use of slicing as given here 
https://docs.python.org/3/library/stdtypes.html#common-sequence-operations 
which I'll leave up to you as an exercise :)

> 
> print(skip_elements(["a", "b", "c", "d", "e", "f", "g"])) # Should be ['a',
> 'c', 'e', 'g']
> print(skip_elements(['Orange', 'Pineapple', 'Strawberry', 'Kiwi',
> 'Peach'])) # Should be ['Orange', 'Strawberry', 'Peach']
> print(skip_elements([ ])) # Should be [ ]
> 
> my output:
> 
> ['a', 'b', 'c', 'd', 'e', 'f', 'g']
> ['Orange', 'Pineapple', 'Strawberry', 'Kiwi', 'Peach']
> []
> 
> 
> output should be:
> 
> ['a', 'c', 'e', 'g']
> 
> ['Orange', 'Strawberry', 'Peach']
> 
> []

-- 
My fellow Pythonistas, ask not what our language can do for you, ask
what you can do for our language.

Mark Lawrence