[Tutor] Count for loops

[D.V.N.Sarma డి.వి.ఎన్.శర్మ]

Modifying the code as shown below may work.

file_path = "C:/Users/Rafael/PythonCode/PiDigits.txt"
with open(file_path) as a:
    b = a.read()

get_year = input("What year were you born? ")

count = 0
for year in b:
    if get_year in b:
        count += 1
print("Your birth date occurs %s times in PI!" % (count))

regards,
Sarma.

On Mon, Apr 3, 2017 at 8:22 PM, Alan Gauld via Tutor <tutor at python.org>
wrote:

> On 03/04/17 13:22, Rafael Knuth wrote:
>
> > with open (file_path) as a:
> >     b = a.read()
> >
> > get_year = input("What year were you born? ")
> >
> > for year in b:
>
> Can you explain what you think this loop line is doing?
> I'm pretty sure it's not doing what you expect.
>
> >     if get_year in b:
> >         print("Your year of birth occurs in PI!")
> >         break
> >     else:
> >         print("Your year of birth does not occur in PI.")
> >         break
> >
> > As a next challenge, I wanted to check how often a person's birth year
> > occurs in PI. Unfortunately, I wasn't able to figure out how to use
> > the loop count properly.
>
> What loop count?
> There is none, its a for loop, no counter needed.
> (OK I just spotted your code below...)
>
> But there is a count() method on a string object that should help.
>
>
> > count = 0
> > for year in b:
> >     if get_year in b:
> >         count += 1
> >     else:
> >         print("Your birth date does not occur in PI.")
> >         break
>
> >     sum_count = sum(count)
>
> sum() sums a sequence, but count is an integer. You have been
> incrementing it as you go, the final value is already there.
>
> --
> Alan G
> Author of the Learn to Program web site
> http://www.alan-g.me.uk/
> http://www.amazon.com/author/alan_gauld
> Follow my photo-blog on Flickr at:
> http://www.flickr.com/photos/alangauldphotos
>
>
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