[Tutor] Need help

[Peter Otten]

niraj pandey wrote:

> Found the solution for this.

You can further simplifiy it with enumerate()
> entry_option = ['Flat_No','Mains Unit','DG Unit','Month']

> entry = {}
> label = {}
  for r, item in enumerate(entry_option):
>     lb = Label(bg = 'orange', text=item, relief=RIDGE,width=30)
>     lb.grid(row=r,column=0)
>     label[item] = lb
>     e = Entry(relief=SUNKEN,width=30)
>     e.grid(row=r,column=1)
>     entry[item] = e
> 
> But now how to pass these values as an argument for this function  ?
> 
> command=lambda: database.data(E1.get(), E2.get(), E3.get(), E4.get())

Well, you saved the Entry instances in a dict, so you can retrieve them:

command=lambda: database.data(*[entry[k].get() for k in entry_option]) 

If you use a list instead of or in addition to the dict

entries = []
for ...: # your loop from above
   ...
   entries.append(e)

the lambda becomes

command=lambda: database.data(*[e.get() for e in entries])

If you have not come across it before: the * operator unpacks the list, so

args = ["a", "b"]
f(*args)

is equivalent to calling f with all items in the list,

f(args[0], args[1])

in the above example.