[Tutor] if then statements

[Mark Lawrence]

On 29/04/2015 02:24, Jacqueline G Solis wrote:
> hello,
>
> I keep getting a syntax error. Could you please explain why that happens and how to correct it.
>
>
> def main ():
>      print( "Welcome to Gonzo Burger!")
>      order= int(input("Enter 1 if you want a hamburger,\
>      or 2 if you want a cheeseburger:" ))
>      if order == 1 :
>                 print("order: 1")
>      else:
>                 print("Order: 2")
>
>      drink=int(input("Thank you! Next, enter a 1 if you want a Coke,\
>      or a 2 if you want a Sprite:")
>      if drink == 1 :
>                print("Order: 1")
>      else:
>                print("Order: 2")
>
>      print("Thank you! You ordered:")
>      if order == 1:
>                print("- Hamburger")
>      else:
>                print("- Cheeseburger")
>      if drink == 1 :
>                print("- Coke")
>      else:
>                print("- Sprite")
>
> main ()
>
>
>
>
> -Jackie
> p.s: the error happens in the second if statement.
>

No it doesn't :)  That's where it gets found, but the error is actually 
before then, and as a learning exercise I'll let you find it.  Look very 
carefully at "order=..." and "drink=..." and I'm sure you'll spot the 
difference.

-- 
My fellow Pythonistas, ask not what our language can do for you, ask
what you can do for our language.

Mark Lawrence