[Tutor] Using subprocess on a series of files with spaces

[C Smith]

Okay I messed up with slash instead of backslash, so the re.sub()
works, but I am still curious about the previous question.

On Thu, Jul 31, 2014 at 6:14 PM, C Smith <illusiontechniques at gmail.com> wrote:
> Even when I am using:
> re.sub('/s', '\\/s', filename)
> I am still getting the same output, even trying to assign the above to
> a new variable doesn't work (as I wasn't sure if re.sub returned a new
> value or changed filename in place, I tried both with)
> Does the Python interpreter strip off backslashes or something with strings?
>
> On Thu, Jul 31, 2014 at 5:53 PM, C Smith <illusiontechniques at gmail.com> wrote:
>>>Change:
>>
>>
>>>subprocess.call(['ffmpeg', '-i', filename, str(track)+'.mp3'])
>>
>>>to:
>>
>>>subprocess.call(['ffmpeg', '-i', '"%s"' % filename, str(track)+'.mp3'])
>>
>> I still get the same errors, the filenames are passed to the shell
>> without escaping the spaces.
>>
>>>Why not using ffmpeg without jumping into Python. It's well documented, check Google.
>>
>> I guess you mean that the ability to change multiple files with ffmpeg
>> is possible. I hadn't considered that but I would rather do it with
>> Python, just for the practice.
>>
>> On Thu, Jul 31, 2014 at 4:36 PM, Emile <emile at salesinq.com> wrote:
>>> On 7/31/2014 1:19 PM, C Smith wrote:
>>>>
>>>> I get
>>>> TypeError: unsupported operand type(s) for %: 'int' and 'str
>>>> I am not understanding the use of the list inside the subprocess.call().
>>>> I tried all of the following
>>>> subprocess.call(['ffmpeg', '-i', '%s', str(track)+'.mp3']) % filename
>>>> --gives type error stated above
>>>> subprocess.call(['ffmpeg', '-i', '%s', str(track)+'.mp3'] % filename)
>>>> --same
>>>> subprocess.call(['ffmpeg', '-i', '%s', str(track)+'.mp3' % filename])
>>>> -- TypeError: not all arguments converted during string formatting
>>>> and tried all three with the triple quotes, just to be sure.
>>>>
>>>> On Thu, Jul 31, 2014 at 4:04 PM, Emile van Sebille <emile at fenx.com> wrote:
>>>>>
>>>>> You might try using '"%s"' % filename so that the name is within quotes
>>>>> for the shell environment.
>>>
>>>
>>> Change:
>>>
>>>
>>> subprocess.call(['ffmpeg', '-i', filename, str(track)+'.mp3'])
>>>
>>> to:
>>>
>>> subprocess.call(['ffmpeg', '-i', '"%s"' % filename, str(track)+'.mp3'])
>>>
>>> Emile
>>>
>>>
>>>