[Tutor] syntax error when attempting simple urllib.request.urlopen item

[Paul Smith]

Tutor-

Ok newbie to coding here attempting to build controlled web scraper and
have followed several books-tutorials and am failing at step one.

This is the 3.3.1 code I am trying to run..
===
import urllib.request

htmltext = urllib.request.urlopen("http://google.com").read

print htmltext
===
Other version...
===
#try py url open 7

import urllib.request
res = urllib.request.urlopen('http://python.org/')
html = res.read()
print = html
close res
input = ("Press enter to exit")
===

so when I run what I think is proper 3.3.1 python code it hangs up with
syntax error with the idle shell red highlighting the last print reference
i.e. "htmltext"  or "html".

What is this humble newbie not getting?

Best regards,

Paul S
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