[Tutor] For - if - else loop; print selective output

[Saad Javed]

Let me modify this example:

a = [['jimmy', '25', 'pancakes'], ['tom', '23', 'brownies'], ['harry',
'21', 'cookies']]
for i in a:
    *b = i[0]*
    if (i[1] == '25' or i[1] == '26'):
        print *b*
    else:
        print 'Not found'

This will output:
*jimmy*
*Not found*
*Not found*
*
*
How do I print positive matches (*jimmy*) only and not (*Not found*). I
also want *Not found *to print only *once *if there are no positive matches.

On Wednesday, October 24, 2012, Saad Javed wrote:

> Hi,
>
> a = [['jimmy', '25', 'pancakes'], ['tom', '23', 'brownies'], ['harry',
> '21', 'cookies']]
> for i in a:
>     if (i[1] == '25' or i[1] == '26'):
>         print 'yes'
> else:
>     print 'Not found'
>
> This prints:
> yes
> not found
>
> I want it to print "yes" for each positive match but nothing for a
> negative match. However if all matches are negative, I want it to print
> "Not found" once (That bit the code already does). I do I get it to print
> "yes" only in a mix result situation?
>
> Saad
>
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