[Tutor] updating step size while in loop

[Wayne Werner]

While you can't do it with a straight generator, you can create your own:

class MyIter:
     def __init__(self, start, stop, step=1):
         self.start = start
         self.stop = stop
         self.step = step
     def __iter__(self):
         self.cur = self.start
         while self.cur < self.stop:
             yield self.cur
             self.cur += 1

And then you could do the following:
In [36]: i = MyIter(1, 10)

In [37]: for x in i:
    ....:     if x % 2:
    ....:         i.cur += 1
    ....:     print(x)
    ....:
1
3
5
7
9

-HTH,
Wayne

On Tue, 10 Jul 2012, Hugo Arts wrote:

> On Mon, Jul 9, 2012 at 11:59 PM, Abhishek Pratap <abhishek.vit at gmail.com>
> wrote:
>       hey guys
>
>       I want to know whether it is possible for dynamically update the
>       step
>       size in xrange  or someother slick way.
>
>       Here is what I am trying to do, if during a loop I find the x in
>       list
>       I want to skip next #n iterations.
> 
>
>       for x in xrange(start,stop,step):
>           if x in list:
>                step = 14
>           else:
>                step = 1
> 
> 
>
>       Thanks!
>       -Abhi
> 
> 
> It is not possible with a range object. You'll have to make a while loop and
> keep track of the step yourself.
> 
> Hugo
> 
>