[Tutor] range question

[Hugo Arts]

forgot to forward to list:

From: Hugo Arts <hugo.yoshi at gmail.com>
Date: Thu, Sep 22, 2011 at 4:42 PM
Subject: Re: [Tutor] range question
To: d at davea.name


On Thu, Sep 22, 2011 at 4:37 PM, Dave Angel <d at davea.name> wrote:
> On 09/22/2011 10:27 AM, Joel Knoll wrote:
>
> Given a range of integers (1,n), how might I go about printing them in the
> following patterns:
> 1 2 3 4 ... n2 3 4 5 ... n 13 4 5 6 ... n 1 2
> etc., e.g. for a "magic square". So that for the range (1,5) for example I
> would get
> 1 2 3 42 3 4 13 4 1 24 1 2 3
> I just cannot figure out how to make the sequence "start over" within a row,
> i.e. to go from 4 down to 1 in this example.
> I have been grappling with this problem for 2.5 days and have gotten
> nowhere!
>
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> Seems like the easiest way would be to duplicate the range once (so you have
> a list twice as long), and then use various slices of it.
>
> x = list(range(1, 5))   #could omit the list() function in python 2.x
> x2 = x+x
>
> for the nth row, use
>    row = x2[n:n+n]
>

Surely you meant to type:

x = list(range(1, 6))
x2 = x + x
row  = x[n:n+len(x)]