[Tutor] How to replace the '\'s in a path with '/'s?

[Richard D. Moores]

On Sun, Jul 31, 2011 at 03:34, Peter Otten <__peter__ at web.de> wrote:
> Sandip Bhattacharya wrote:
>
>> On Sat, Jul 30, 2011 at 10:28:11PM -0700, Richard D. Moores wrote:
>>> File "c:\P32Working\untitled-5.py", line 2
>>>    return path.replace('\', '/')
>>>                                ^
>>> SyntaxError: EOL while scanning string literal
>>> Process terminated with an exit code of 1
>>
>> The first backslash up there is escaping the ending quote. This is  what
>> you want:
>>     return path.replace('\\', '/')
>>
>> Generally, converting slashes manually should be kept at a minimum. You
>> should be using library functions as much as possible. The experts here
>> can correct me here, but this is a roundabout way I would be doing this:
>>
>>     # I use a linux machine. Using this to work with Windows paths
>>     # Use os.path if you are on windows
>>     import ntpath
>>
>>     # Use raw strings so that backslash doesnt matter
>>     path=r'C:\Users\Dick\Desktop\Documents\Notes\College Notes.rtf'
>>
>>     #take out drive first because ntpath.split end sentinel is predictable
>>     #that way
>>     drive,rest = ntpath.splitdrive(path)
>>
>>     # This will store the path components
>>     comps = []
>>     comps.append(drive)
>>
>>     while rest != '\\':
>>         parts = ntpath.split(rest)
>>         comps.insert(1,parts[1])
>>         rest = parts[0]
>>
>>
>>     print '/'.join(comps)
>>
>> I am not happy with the loop to collect the components. But I couldn't
>> find a single path function which splits a path into all the components
>> in one go.
>
> What happens if the path looks like
>
> r"C:relative\path\to\my\file.txt"
>
> or
>
> r"C:/mixed\slashes.txt"?

Not quite sure what the intent of your question is, but all the paths
I want to modify are full, with only back slashes.

Dick