[Tutor] what is 'doubleword alignment'?

[Alan Gauld]

Dave Angel wrote:
>> --- On Sat, 7/16/11, Albert-Jan Roskam<fomcl at yahoo.com>  wrote:

>> (in my case 8 bytes) is aligned in the computer's memory such that the 
>> boundary's address is a power of two.
> Not quite.  Doubleword alignment is alignment on an 8byte boundary.  The 
> address of such a boundary will be a multiple of 8, not a power of two.

Oops, when I said Albert was "right" I meant in terms of aligning with 
computer memory, I didn't register the "power of two" bit, which is, as 
you say, not correct. Apologies for any confusion caused!


Alan G.