[Tutor] Help with range of months spanning across years

[ian douglas]

It bugs me that so many people are quick to jump on the "we wont' do 
your homework" bandwagon -- I was accused of the same thing when I 
posted a question to the list myself. I've been programming 
professionally for many years but learning Python in my spare time... I 
sent this reply to Sean privately, but frankly I'm so annoyed at the 
'homework' replies, I figured I'd just post it here.

I'm still very junior to Python, but this seems to work for me using 
recursion. I'm sure there's a much more elegant way of doing this, but 
like I said, I'm still pretty new to the language.

def makelist(startmonth,startyear,endmonth,endyear):
     mylist = []
     if (startyear == endyear):
         for month in range (startmonth,endmonth+1):
             mylist += [(startyear,month)]
     else:
         for month in range (startmonth,13):
             mylist += [(startyear,month)]
         mylist += makelist(1,startyear+1, endmonth, endyear)
     return mylist ;

print makelist(8,2009,1,2010)

I'd love to hear any replies from the experts on the list on how to make 
this more efficient in Python 'cause I'm still learning myself.


On 02/01/2011 05:14 PM, Elwin Estle wrote:
> --- On Tue, 2/1/11, Sean Carolan<scarolan at gmail.com>  wrote:
>
>> What would be the most straightforward way to create a list
>> of
>> year/month pairs from start to end?  I want to end up
>> with a list of
>> tuples like this:
>>
>> mylist = [(2009, 8), (2009, 9), (2009, 10), (2009, 11),
>> (2009, 12), (2010, 1)]
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