[Tutor] timedelta, difference calculation
Timo
timomlists at gmail.com
Tue Dec 13 12:10:46 CET 2011
Op 12-12-11 20:46, rail shafigulin schreef:
> i found something interesting during the timedate difference calculation
>
> import datetime
> import time
>
> def main():
> mydatetime = datetime.datetime.now()
> time.sleep(1)
> mydatetime2 = datetime.datetime.now()
> diff = mydatetime - mydatetime2
Lie Ryan explains how to read the output below, but you made a little
error here.
Let's have a little example:
>>> x1 = 1
>>> x2 = x1 + 1
>>> print(x1 - x2)
-1
>>> print(x2 - x1)
1
So you should substract mydatetime from mydatetime2, not the other way
around.
Cheers,
Timo
>
> print(diff)
>
> if __name__ == '__main__':
> main()
>
> if you run this code the result you get will be
> -1 day, 23:59:59
>
> at least that is what i'm getting.
>
> i was expecting to get -1 second. diff object is of type timedelta.
> this kind of objects represent duration, at least that is what i
> understood from the documentation
> (http://docs.python.org/release/3.1.3/library/datetime.html#timedelta-objects).
> so, is this a bug in the timedelta implementation or is it me not
> understanding documentation properly?
>
> any help is appreciated.
>
> ps. i'm using python 3.1 on a windows xp machine.
>
>
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