[Tutor] Python Help

[masawudu bature]

Thanks David, But the loop was suppose to produce the count of even divisors an 
integer has.
Like, 6 has 2 "even" divisors, which is 2 and 6, itself.
8 = 3 even divisors, which is 2, 4 ,and 8
10 = 2 even divisors, which is 2, and 10
12 = 4 even divisors, which is 2, 4, 6, and 12

sorry, I just don't know how to write a code to count the number of divisors




________________________________
From: David Hutto <smokefloat at gmail.com>
To: masawudu bature <mass02gh at yahoo.ca>
Cc: tutor at python.org
Sent: Mon, September 27, 2010 11:36:05 PM
Subject: Re: [Tutor] Python Help

On Tue, Sep 28, 2010 at 12:15 AM, masawudu bature <mass02gh at yahoo.ca> wrote:
> I'm having a hard time finding the count of divisors that are even. Help
> anybody?
>
> Here's my code.
>
> The output is suppose to count the number of even divisors the range has.
>
> def evenCount(b) :
>     for n in range(x, y+1) :
>         count = 0
>         if n % 2 == 0 :
>             count += n/3
>             count % n == 1
>         return n
>
>
> ### main ####
>
> x = input("Enter a starting value: ")
> y = input("Enter a stopping value: ")
>
> count = evenCount(x)
>
> for n in range(x, y+1) :
>     count = 0
>     if n % 2 == 0 :
>         count += n/3
>         print "%2d: " %n, "has%2d" %count, "even divisors",
>     else :
>         print "%2d: " %n, "has 0 even divisors",
>     print
>
>
>
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#You start with your range variables
x = input("Enter a starting value: ")
y = input("Enter a stopping value: ")

#You set a for loop for range
for num in range(x, y):
#If that number divided by 2 has a remainder of 0, it's of course even.
    if num % 2 == 0:
    #print the number
            print num

And various other ways as well.

David



      
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