[Tutor] How to numerically sort strings that start with numbers?

[David Hutto]

On Mon, Sep 13, 2010 at 9:11 PM, Adam Bark <adam.jtm30 at gmail.com> wrote:
> On 14/09/10 01:11, Pete O'Connell wrote:
>>
>> theList = ["21 trewuuioi","3zxc","134445"]
>> print sorted(theList)
>>
>> Hi, the result of the sorted list above doesn't print in the order I
>> want. Is there a straight forward way of getting python to print
>> ['3zxc','21 trewuuioi','134445']
>> rather than ['134445', '21 trewuuioi', '3zxc']?
>>
>> Any help would be greatly appreciated
>> Pete
>>
>
> print sorted(theList)[::-1]
>
> as list indices go [start:end:step] what this means is the whole list
> starting from the end and working backwards.
> You can also have a look at reversed() if you want an iterator or you can
> use theList.reverse() if you want to reverse in place ie.
>
>>>> l = ["21 trewuuioi","3zxc","134445"]
>>>> l.reverse()
>>>> print l
> ['134445', '3zxc', '21 trewuuioi']
>
>
> HTH
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Thanks from me too, because I kept getting None when trying
to directly print theList.reverse()

>>> theList = ["21 trewuuioi","3zxc","134445"]
>>> theList.reverse()
>>> print theList
['134445', '3zxc', '21 trewuuioi']
>>> print theList.reverse()
None
>>> print type(theList.reverse())
<type 'NoneType'>
>>> print type(theList)
<type 'list'>
>>>