[Tutor] exercise correct ??

[ALAN GAULD]

Oke, the 4 is a starting point for the index.
> 
>Next problem.
> 
>The begin looks like this :
> 
> index_of(5, (1, 2, 4, 5, 6, 10, 5, 5), 4)
>
>But in the module I get this result :
> 
>val = 5
>seq = (1, 2, 4, 5, 6, 10, 5, 5
> 
>So the 4 is not avaible anymore.
>
Yes it is. It is the start parameter.

The function definition is

def index_of(val, seq, start=0):

val is the first value, 5, seq is the tuple and start is 4.
 

Now I can change the header to  index(val, seq, start=0) to index (val, seq, 
start)
>But I think that's not what the exercise wants.
>
Why would you want to do that? It would force you to provide a start value 
for every call. The point of having a default value (=0) is so that you do not 
need to specify start every time you use the function. But eveb if you do not
use the start value it will still have a value, 0.
There is no difference, you can access it exactly like the other parameters.
Just use its name.
 
HTH,

Alan G.
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