[Tutor] Calculating and returning possible combinations ofelements from a given set

[ZUXOXUS]

2010/7/28 Alan Gauld <alan.gauld at btinternet.com>

>
> "ZUXOXUS" <zuxoxus at gmail.com> wrote
>
>
>
>  My doubt now is whether I can change the way python show the combinations.
>>
>
> Python will display the compbinations however you tell it to.
> The function generates the combinations the display is up to you.
> In this case you are simply printing the results as they come.
> But you can put them in a list if you prefer.
>
>  prodList = []
>>>>
>>>> for prod in itertools.product('abc', repeat=3):
>>>>
>>> ...           prodList.append(prod)
> ...
>
>> print prodList
>>>>
>>>
> You can manipulate prod however you like before putting it inthe list.
> Once you have the list you can sort that list to get anyorder you want.
> And once you have your soted and formatted list you can print it out
> using whatever formatting you want.
>
> It is always good to separate the generation of data fropm the
> storage of data from the display of data.
>
>
>  I have checked how the function works (see below), perhaps I have to just
>> change couple of lines of the code and voilá, the result displayed as I
>> want... But unfortunately I'm too newbie for this, or this is too
>> hardcore:
>>
>
> Its hardly ever a good idea to modify the standard library functions.
> You can write a wrapper around them if you like - and indeed thats normal.
> But changing them is almost always a very bad  idea!
>
> def myProduct(*args, **kwds):
>    # do something with input data
>    # call itertools.product(args, kwds)
>    # do something with the output
>    # return a result
>
> HTH,
>
> --
> Alan Gauld
> Author of the Learn to Program web site
> http://www.alan-g.me.uk/
>
>
>
> _______________________________________________
> Tutor maillist  -  Tutor at python.org
> To unsubscribe or change subscription options:
> http://mail.python.org/mailman/listinfo/tutor
>


Hi Alan and everybody

Well, that is not exactly what I expected, but can help

>>> lista = []
>>> for prod in itertools.product('aei', repeat=2):
lista.append(prod)
print(lista)

[('a', 'a')]
[('a', 'a'), ('a', 'e')]
[('a', 'a'), ('a', 'e'), ('a', 'i')]
[('a', 'a'), ('a', 'e'), ('a', 'i'), ('e', 'a')]
[('a', 'a'), ('a', 'e'), ('a', 'i'), ('e', 'a'), ('e', 'e')]
[('a', 'a'), ('a', 'e'), ('a', 'i'), ('e', 'a'), ('e', 'e'), ('e', 'i')]
[('a', 'a'), ('a', 'e'), ('a', 'i'), ('e', 'a'), ('e', 'e'), ('e', 'i'),
('i', 'a')]
[('a', 'a'), ('a', 'e'), ('a', 'i'), ('e', 'a'), ('e', 'e'), ('e', 'i'),
('i', 'a'), ('i', 'e')]
[('a', 'a'), ('a', 'e'), ('a', 'i'), ('e', 'a'), ('e', 'e'), ('e', 'i'),
('i', 'a'), ('i', 'e'), ('i', 'i')]
>>>


Now I only need to put together in a single string all the elements that are
grouped in parentheses, I think I can do that

Thank you very much!
-------------- next part --------------
An HTML attachment was scrubbed...
URL: <http://mail.python.org/pipermail/tutor/attachments/20100728/81ed531e/attachment.html>