[Tutor] elif statement

[Sudarshana Banerjee]

Hi: Thank you very much for the detailed reply. My problem is I know I am
doing the indentation wrong; but I cannot get it right in IDLE.

Could you take a look at this please:
>>> x=3
>>> if x==0:
print "x is 0"

>>> elif x&1==1:
SyntaxError: invalid syntax

See, the moment I am pressing Enter the >>> is coming.. not ...

I am using IDLE on Mac; and this is driving me crazy! :) I can get the
result if I combine the if and print statements in one line.. but I really
want to know what is going on.

On Wed, Aug 11, 2010 at 1:22 AM, Dipo Elegbede <delegbede at dudupay.com>wrote:

> You need to check the indentation properly.
> In this case, elif has to be on the same indentation level with if. I
> should think so.
> If you're working straight from the python interactive console, like I
> think you're doing, you need to manually do the indentation thing by
> yourself.
> First, I don't understand why you chose to set x to 3. That is not the
> main thing though.
> After x = 3, if you press enter, you'd get the python prompt
> >>>
> Then you type the next statement to have
> >>> if x == 0:
> What you get after this if statement is either a whitespace or ...,
> from my phone, I get a ...
> So you manually press the spacebar twice to get an indentation for the
> first print statement.
> As soon as you press enter again, you get the dots, just type in the
> elif statements without pressing the spacebar. Then press enter to
> move to a new line where the second print statement would be,and press
> the spacebar twice again for indentation.
> For the second elif statement, follow the procedure for the first elif
> statement.
> Go ahead and press enter twice to tell the console you are done, you
> shouldn't get an error that way.
> You should get something like below:
>
> >>> x=3
> >>> if x==0:
> ...   print x,'is zero'
> ... elif x//1==1:
> ...   print x,'is odd'
> ... elif x//1==0:
> ...   print x,'is even'
> ... else:
> ...   print'what is this'
> ...
>
> The else statement is optional.
> Hope it helps.
>
> On 8/11/10, Adam Bark <adam.jtm30 at gmail.com> wrote:
> > On 11/08/10 02:34, Sudarshana Banerjee wrote:
> >> Hi: I am trying to teach myself Python, and am stuck at the
> >> indentation with the elif statement.
> >>
> >> This is what I am trying to type (as copied from the textbook):
> >>
> >> x=3
> >> if x==0:
> >>     print "x is 0"
> >> elif x&1 ==1:
> >>     print "x is a odd number"
> >> elif x&1==0: -- Line 6
> >>     print "x is a even number"
> >>
> >> If I am combining the if and the print statement, then the elif
> >> statement is in the next line, and all is well with the world. If
> >> however, I write the print as a separate statement, I am getting a
> >> syntax error after I press Enter after keying the first elif statement.
> >>
> >> >>> x=3
> >> >>> if x==0:
> >> print x
> >> elif x==2:
> >
> > Here you have indented the elif statement but it should be at the same
> > level as the if:
> >  >>> x=3
> >  >>> if x==0:
> > ...     print x
> > ... elif x==2:
> > ...     print "something else"
> > ...
> >  >>>
> >
> >
> >> SyntaxError: invalid syntax
> >>
> >> Again:
> >> >>> x=3
> >> >>> if x==2: print x
> >> elif x&1 == 1: print 'x is odd'
> >> >>> elif x&1 ==0: print 'x is even'
> >> SyntaxError: invalid syntax
> >
> > I'm not sure what's going on here but the second elif is being
> > interpreted separate to the rest of the if statement hence a SyntaxError:
> >  >>> elif x&1 == 0: print "x is even"
> >    File "<stdin>", line 1
> >      elif x&1 == 0: print "x is even"
> >         ^
> > SyntaxError: invalid syntax
> >
> > This works:
> >  >>> if x==2: print x
> > ... elif x&1 == 1: print 'x is odd'
> > ... elif x&1 ==0: print 'x is even'
> > ...
> > x is odd
> >
> >
> >>
> >> If I am pressing two Enters, the code executes; so I have a elif
> >> without a if, and again, a syntax error. What am I not doing right?
> >>
> >> Thank you.
> >>
> >> Sudarshana.
> > HTH,
> > Adam.
> >
> >
> >
>
>
> --
> Elegbede Muhammed Oladipupo
> OCA
> +2348077682428
> +2347042171716
> www.dudupay.com
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