[Tutor] How to control the not existent keys in a dict
Richard Lovely
roadierich at googlemail.com
Mon May 11 05:41:24 CEST 2009
2009/5/10 Emilio Casbas <ecasbasj at yahoo.es>:
>
> Hello,
>
> I have some problems testing keys not existent in a dictionary.
> The code works testing existent keys with his corresponding value, but
> If I enter a not existent key, an exception is raised.
> How can I control the not existent key and assign him a default value?
>
> user at cipher:~/project/programming/python$ python3.0 test.py
> ¿What is your name? KEY-NOT-EXISTENT
> Good Morning KEY-NOT-EXISTENT
> ¿Which is the secret word? any
> Traceback (most recent call last):
> File "test.py", line 30, in <module>
> while not correct_password(name,guess,dictionary):
> File "test.py", line 8, in correct_password
> if (is_in_dict and password == dict[nombre.capitalize()]):
> KeyError: 'KEY-NOT-EXISTENT'
>
> -relevant code snippet-
> dictionary = {'Mark': 'python', 'Dave': 'java', 'Ane': 'C++', 'default':'pass'}
>
> def correct_password(name,password,dict):
> if (not is_in_dict and password == dict['default']):
> return 1
> elif (is_in_dict and password == dict[nombre.capitalize()]):
> return 1
> return 0
>
> def is_in_dict(nom,dict):
> for n in dict:
> if nom.lower() == n.lower():
> return 1
> return 0
> -end relevant code snippet-
>
> Regards
>
>
>
>
> _______________________________________________
> Tutor maillist - Tutor at python.org
> http://mail.python.org/mailman/listinfo/tutor
>
There's also collections.defaultdict, which you can initialise with a
"default value factory" which will generate a value for every attempt
to get a non-existent key. It can be a lot of fun with a bit of
thought.
--
Richard "Roadie Rich" Lovely, part of the JNP|UK Famile
www.theJNP.com
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