[Tutor] Handling Generator exceptions in Python 2.5

[Alan Gauld]

"Joe Python" <jopython at gmail.com> wrote

> *result = [(ListA[i] - ListB[i-1])/ListA[i] for i in range(len(ListA))]*
>
> The above generator, throws  '*ZeroDivisionError*' exception if ListA[i] 
> =
> 0.
> Is there a way to say 'Don't divide by ListA[i] if its equal to 0 (within
> that statement)'.

You could use an 'or' sideffect

result = [(ListA[i] - ListB[i-1])/(ListA[i] or 1) for i in 
range(len(ListA))]

But whether dividing by 1 as a default makes any sense will be a
choice depending on the application and data.

Alan G