[Tutor] Quick question regarding Parsing a Delimited string

[Garry Bettle]

Hi,

I've been programming for over 20 yrs, but only the last few in python
and then only in dribs and drabs.

I'm having a difficult time parsing a delimited string.

e.g.

100657641~GBP~ACTIVE~0~1~~true~5.0~1247065352508~:
3818854~0~24104.08~4.5~~22.1~false|4.4~241.67~L~1~4.3~936.0~L~2~4.2~210.54~L~3~|4.5~19.16~B~1~4.6~214.27~B~2~4.7~802.13~B~3~:
3991404~1~19974.18~4.7~~21.7~false|4.6~133.01~L~1~4.5~124.83~L~2~4.4~319.33~L~3~|4.7~86.61~B~1~4.8~247.9~B~2~4.9~142.0~B~3~:
4031423~2~15503.56~6.6~~15.1~false|6.6~53.21~L~1~6.4~19.23~L~2~6.2~53.28~L~3~|6.8~41.23~B~1~7.0~145.04~B~2~7.2~37.23~B~3~

That is just a selection of the full string - and I've broken it up
for this email.  It's delimited by : and then by ~ and finally, in
some cases, | (a pipe).

If the string is called m, I thought I could create a list with
m.split(":").  I would like to then first of all find in this list the
entry beginning with e.g. 3991404.

I thought I could pop each item in the list and compare that seems
pretty long winded.

When the ItemFound is now =
'3991404~1~19974.18~4.7~~21.7~false|4.6~133.01~L~1~4.5~124.83~L~2~4.4~319.33~L~3~|4.7~86.61~B~1~4.8~247.9~B~2~4.9~142.0~B~3~:'

I would like to return the 3rd item delimited with ~, which in this case, is 4.7

Can anyone help?

Many thanks!

Cheers,

Garry