[Tutor] using datetime and calculating hourly average

[John [H2O]]

Sanders,

The problem is I don't want date, I want the date AND hour, just not
minutes.

As for the comparison, in numpy here's what happens when I change the way I
construct the where statements:

--> 196         ind = np.where( (t1 < Y[:,0] < t2) ) #same result
with/without inner parens
    197         screen_vals = Y[ind,1][0]
    198         #print 'X time: %s' % t1

TypeError: can't compare datetime.datetime to numpy.ndarray


OR trying the 'and' method:

--> 196         ind = np.where( (Y[:,0]>t1) and (Y[:,0]<t2) )
    197         #ind = np.where( (t1 < Y[:,0] < t2) )

    198         screen_vals = Y[ind,1][0]

ValueError: The truth value of an array with more than one element is
ambiguous. Use a.any() or a.all()

Seems I might want to try and get some help over on the numpy list as was
mentioned, but I'll check back here for suggestions!

Thanks!


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