[Tutor] list objects are unhashable

[Norman Khine]

Hi,


Alan Gauld wrote:
> 
> "Norman Khine" <norman at khine.net> wrote
> 
>> Here is the 'full' code as such which gets the data from the files.
> 
> Unfortunately trying to read this is still difficult since we don't
> know what the structure of x, horizontal_criterias, vertical_criterias,
> or brains is like.

Here is the code http://www.pastie.org/225436


> 
>>         ## Classify the users
>>         table = {}
>>         table[('', '')] = 0
>>         for x in horizontal_criterias:
>>             table[(x['id'], '')] = 0
>>         for y in vertical_criterias:
>>             table[('', y['id'])] = 0
>>         for x in horizontal_criterias:
>>             x = x['id']
> 
> You select a collection of some sort and replace it with a value
> from the collection. Is that really what you want to do? You don't
> do it for y...



> 
>>             for y in vertical_criterias:
>>                 table[(x, y['id'])] = 0
> 
> It would be just as readable IMHO to just use
> 
>          table[ x['id'],y['id'] ] = 0
> 
Here I get an error

Traceback (most recent call last):
   File 
"/Users/khinester/Sites/itools/0.16.9/Python-2.5.1/lib/python2.5/site-packages/abakuc/training.py", 
line 531, in statistics
     table[ x['id'],y['id'] ] = 0
TypeError: string indices must be integers


>>         for brain in brains:
>>             x = getattr(brain, horizontal)
>>             if isinstance(x, list):
>>                 for item in x:
>>                     x = item
> 
> And here you replace the list x with it' first item.
> You could just do
> 
> x = x[0]

Here is my issue, as I would like to count each item in the list and 
place it in the table, but don't see how to do it.

> 
>>             else:
>>                 x
> 
> And this does nothing useful whatsoever. It just
> siilently evaluates x.

Removed.
> 
>>             y = getattr(brain, vertical)
>>             if isinstance(y, list):
>>                 for item in y:
>>                     y = item
>>             else:
>>                 y
> 
> Same comments apply
> 
>>             if x and y and (x, y) in table:
>>                 table[(x, y)] += 1
>>                 table[(x, '')] += 1
>>                 table[('', y)] += 1
>>                 table[('', '')] += 1
>>
>>
>> table is a dictionary, which returns, for example:
>>
>> {   ('', ''): 1,
>>     ('', 'fr'): 0,
>>     ('airport-car-parking', ''): 2,
>>     ('airport-car-parking', 'fr'): 0,
>>     ('air-taxi-operators', ''): 1,
>>     ('air-taxi-operators', 'fr'): 0,
>>      ...
>>     ('worldwide-attractions-and-ticket-agents', ''): 0,
>>     ('worldwide-attractions-and-ticket-agents', 'fr'): 0,
> 
>> From this I suggest you rename your variable from x and y
> to something meaningful like facility and country. That
> might make your code more meaningful to read.
> 
>> The output is something like:
>> country |airport-car|air-taxi-operators|airlines-schedule| total
>> ---------------------------------------------------------------
>> france  |0     |0        |0 |0
>> uk |2     |0        |0 |2
>> us |0          |0        |0 |0
>> ---------------------------------------------------------------
>> total |2     |0                 |0 |2
>> ---------------------------------------------------------------
>>
>> What I can't seem to figure out is how to do a cumulative sum for each 
>> record, for example, my files contain:
> 
> Frankly I'd use a database. Just load the data into it using Python.
> Then execute SQL querioes to get the counts etc.

Not really an option to use SQL just for this.

> 
>>             if isinstance(x, list):
>>                 for item in x:
>>                     x = item
>>     pp.pprint(x)
>>             else:
>>
>> Which is correct, but the table only counts the first item of the tuple.
> 
> Isn't that because you replace x with the first element of x?

As mentioned above, I know this, but I would like to find out how to do 
it so that it counts each item in the list.

> 
> Alan G.
> 
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