[Tutor] trouble with if

[Aditya Lal]

I think you need to use "raw_input" instead of "input". input "eval" the
input expression while "raw_input" just stores it. I find the module help
very handy when I am in doubt.

>>> print raw_input.__doc__
raw_input([prompt]) -> string

Read a string from standard input.  The trailing newline is stripped.
If the user hits EOF (Unix: Ctl-D, Windows: Ctl-Z+Return), raise EOFError.
On Unix, GNU readline is used if enabled.  The prompt string, if given,
is printed without a trailing newline before reading.

>>> print input.__doc__
input([prompt]) -> value
Equivalent to eval(raw_input(prompt)).


On 10/26/07, Bryan Fodness <bryan.fodness at gmail.com> wrote:
>
> I cannot get this to work either.
>
> woffaxis = 7
>
> if woffaxis != 0:
>      woaf_pos = input("What is Wedge Direction (N/A, Lateral, Towards
> Heal, Towards Toe)?")
>
> if woaf_pos == 'Towards Toe':
>      woffaxis = woffaxis
> elif woaf_pos == 'Towards Heal':
>      woffaxis = (woffaxis * -1)
> else:
>      woffaxis = 0
>
>
>
>
>
>
> On 10/24/07, John Fouhy <john at fouhy.net> wrote:
> >
> > On 25/10/2007, Bryan Fodness <bryan.fodness at gmail.com> wrote:
> > > I have the following code, it keeps giving me a value of 1 for e.
> > >
> > > for line in file('21Ex6MV_oaf.dat'):
> > >     oa, openoa, w15, w30, w45, w60 = line.split()
> > >     if (float(oa) == round(offaxis)) and (eff_depth < 10 and
> > unblockedFS >
> > > 15):
> > >         e = float(openoa)
> > >     else:
> > >         e = 1
> > >
> > > If I comment out the else, I get the correct value
> > >
> > > for line in file('21Ex6MV_oaf.dat'):
> > >     oa, openoa, w15, w30, w45, w60 = line.split()
> > >     if (float(oa) == round(offaxis)) and (eff_depth < 10 and
> > unblockedFS >
> > > 15):
> > >         e = float(openoa)
> > > #    else:
> > > #        e = 1
> >
> > Maybe you need a 'break' statement after 'e = float(openoa)'?
> >
> > As written, e will have whatever value is appropriate for the last
> > line of your input file.
> >
> > --
> > John.
> >
>
>
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>
>


-- 
Aditya
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