[Tutor] itertools.izip question?

[Iyer]

I have a dictionary

d = {0: array([0, 0], dtype=uint16), 1: array([1, 1], dtype=uint16), 2: array([2, 2], dtype=uint16), 3: array([3, 3], dtype=uint16)}
or 
d = {0:d0,1:d1,2:d2,3:d3}


d0, d1, d2 and d3 are numpy.ndarray type 

I wish to get the interleaved data by using  

outputdata = numpy.array([item for items in itertools.izip(d.values()) for item in items])

But I get outputdata = array([[0, 0],       [1, 1],      [2, 2],       [3, 3]], dtype=uint16)

which is different from the desired answer, which can be obtained by 

outputdata = numpy.array([item for items in itertools.izip(d0,d1,d2,d3) for item in items])

outputdata = array([0, 1, 2, 3, 0, 1, 2, 3], dtype=uint16)

I notice that when outputdata = numpy.array([item for items in itertools.izip((d0,d1,d2,d3)) for item in items]) is used, 

outputdata = array([[0, 0],       [1, 1],       [2, 2],       [3, 3]], dtype=uint16)

Is there any way to izip over dictionary values d.values() and obtain 

outputdata = array([0, 1, 2, 3, 0, 1, 2, 3], dtype=uint16)
    

I'm stumped a bit by this itertools izip behavior, suggestions appreciated.

~iyer

       
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