[Tutor] Yet another list comprehension question
Smith, Jeff
jsmith at medplus.com
Fri Mar 2 16:18:18 CET 2007
I find a common thing to do is
l = list()
for i in some-iterator:
if somefum(i) != list:
l.append(somefun(i))
In other words, applying somefun to the results of the iterator return
duplicates but I want the constructed list to contain none.
l = [somefun(i) for i some-iterator]
will produce the redundancies
l = [somefun(i) for i some-iterator if somefun(i) not in l]
doesn't work (not that I expected it to).
Is there a more Pythonic idiom to do this than the for/if block?
Thanks,
Jeff
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